The period of $f(x)=\sin 3 \pi\{x\}+\tan \pi[x]$ is :

0 1 $\pi$ None of these

1

tan π {x} = 0 because π {x} will always be integral multiple of π ⇒ f(x) = sin 3π {x} Hence period of f(x) is 1 Hence (2) is the correct answer.