A spider climbed 37\(\frac{1}{2}\)% of the height of a pole in one hour and in the next hour it covered 20% of the remaining height. If pole's height is 200m, then the distance climbed in second hour is:
Answer & explanation
Correct answer: option 1
37\(\frac{1}{2}\)% = \(\frac{3}{8}\) and 20% = \(\frac{1}{5}\)
Height covered in 1st hour:
⇒ 200 × \(\frac{3}{8}\) ⇒ 75 m
Remaining height⇒ 200-75 = 125 m
Height covered in 2nd hr:
⇒ 125 × \(\frac{1}{5}\) = 25m