A spider climbed 37\(\frac{1}{2}\)% of the height of a pole in one hour and in the next hour it covered 20% of the remaining height. If pole's height is 200m, then the distance climbed in second hour is:

25m

37\(\frac{1}{2}\)% = \(\frac{3}{8}\) and  20% = \(\frac{1}{5}\)

Height covered in 1st hour:

⇒ 200 × \(\frac{3}{8}\) ⇒ 75 m

Remaining height⇒ 200-75 = 125 m

Height covered in 2nd hr:

⇒ 125 × \(\frac{1}{5}\) = 25m