Van’t Hoff factor for a dilute solution of sodium argento cyanide is:

2

The correct answer is option 1. 2.

To determine the Van’t Hoff factor \((i)\) for a dilute solution of sodium argento cyanide, let us first understand what sodium argento cyanide is:

Sodium argento cyanide is a compound with the formula \( \text{Na[Ag(CN)}_2] \). It dissociates in water as follows:

\(\text{Na[Ag(CN)}_2] \longrightarrow \text{Na}^+ + \text{[Ag(CN)}_2]^-\)

From this dissociation equation, we see that one formula unit of sodium argento cyanide produces:

1 \(\text{Na}^+\)

1 \(\text{[Ag(CN)}_2]^-\)

Thus, the total number of ions produced is 2.

The Van’t Hoff factor \((i)\) is the ratio of the actual number of particles in solution after dissociation to the number of formula units initially dissolved:

\(i = \text{Number of ions produced per formula unit} \)

For sodium argento cyanide, \(i = 2\)

The Van’t Hoff factor for a dilute solution of sodium argento cyanide is: 2.