The set of all x for which $1+\log x<x$, is
Answer & explanation
Correct answer: option 1
$1+\log x<x$
so $\log x < x-1$
$⇒x<e^{x-1}$
$⇒x∈(1, \infty)$
The set of all x for which $1+\log x<x$, is
Correct answer: option 1
$1+\log x<x$
so $\log x < x-1$
$⇒x<e^{x-1}$
$⇒x∈(1, \infty)$