Using algebraic identities, simplify the following expression. $\frac{(x^4+x^2+1)}{(x^2+x+1)}$

$(x^2-2x+1)$ $(x^2+x+1)$ $(x^2+ 2x+1)$ $(x^2-x+1)$

$(x^2-x+1)$

$\frac{(x^4+x^2+1)}{(x^2+x+1)}$ We know that, x4 + x2y2 + y4 = (x2 – xy + y2) (x2 + xy + y2) $\frac{(x^2+x+1)(x^2-x+1)}{(x^2+x+1)}$ = $(x^2-x+1)$