Practicing Success
If x, y, z are three integers such that x + y = 8, y + z = 13 and z + x = 17, then the value of $\frac{x^2}{yz}$ is: |
$\frac{7}{5}$ $\frac{18}{11}$ 0 1 |
$\frac{18}{11}$ |
x + y = 8 y + z = 13 z + x = 17 ——————————— 2( x + y + z) = 38 x + y + z = 19 Now , (x + y + z ) - (x + y) = 19 - 8 z = 11 (x + y + z ) - (z + y) = 19 - 13 x = 6 (x + y + z ) - (x + z) = 19 - 17 y = 2 $\frac{x^2}{yz}$ = $\frac{6^2}{2 \times 111}$ = \(\frac{36}{22}\) $\frac{x^2}{yz}$ = $\frac{18}{11}$ |