If x, y, z are three integers such that x + y = 8, y + z = 13 and z +…

      x + y = 8

      y + z = 13

     z + x = 17

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   2( x + y + z) = 38

x + y + z = 19

Now ,

(x + y + z ) - (x + y) = 19 - 8

z = 11

(x + y + z ) - (z + y) = 19 - 13

x = 6

(x + y + z ) - (x + z) = 19 - 17

y = 2

$\frac{x^2}{yz}$ = $\frac{6^2}{2 \times 111}$ = \(\frac{36}{22}\)

$\frac{x^2}{yz}$ = $\frac{18}{11}$