Practicing Success
Practicing Success
CUET Preparation Today
$\frac{secθ+tanθ}{secθ-tanθ}$ is equal to: |
$\frac{1}{secθ-tanθ}$ $\frac{1}{secθ+tanθ}$ $(secθ+tanθ)^2$ $(secθ-tanθ)^2$ |
$(secθ+tanθ)^2$ |
$\frac{secθ+tanθ}{secθ-tanθ}$ = \(\frac{secθ+tanθ }{secθ-tanθ}\) × \(\frac{secθ+tanθ }{secθ+tanθ}\) = \(\frac{ (secθ+tanθ)² }{sec²θ-tan²θ}\) We know , sec²θ - tan²θ = 1 = \(\frac{ (secθ+tanθ)² }{1}\) = (secθ+tanθ)² |
