Practicing Success
Given $A=\left[\begin{array}{ll}2 & 3 \\ 1 & 4\end{array}\right]$ and $B=\left[\begin{array}{ll}x & y \\ 1 & 4\end{array}\right]$, If $A=B$, then $x$ and $y$ are : |
$x=2, y=3$ $x=1, y=2$ $x=3, y=2$ $x=-2, y=-3$ |
$x=2, y=3$ |
$A=\left[\begin{array}{ll}2 & 3 \\ 1 & 4\end{array}\right]$ $B=\left[\begin{array}{ll}x & y \\ 1 & 4\end{array}\right]$ Given A = B ⇒ their order is same as well as each of their respective elements are same So $x=2, y=3$ |