If $A = \{a, b\}, B = \{c, d\}, C= \{d, e\}$, then $\{(a, c), (a, d), (a, e), (b, c), (b, d), (b, e)\}$ is equal to

$A×(B∪C)$

The correct answer is Option (3) → $A×(B∪C)$

Clearly, the set of first elements of ordered pairs in the given set is $\{a, b\}$ and the set of second elements is $\{c, d, e\}$.

$∴\{(a, c), (a, d), (a, e), (b, c), (b, d), (b, e)\}$

$= \{a, b\} × \{c, d, e\} = A×(B∪C)$