The adjoint of the matrix A=≤ft[ […] ] is

$A=\left[\begin{array}{cc} 1 & 2 \\ 3 & -5 \end{array}\right]$

The co-factors are given by,

$A_{11}=-5 ; A_{12}=-3 ; A_{21}=-3 ; A_{22}=1$

Let, $B ⥂~=\left[\begin{array}{ll}A_{11} & A_{12} \\ A_{21} & A_{22}\end{array}\right]=\left[\begin{array}{cc}-5 & -3 \\ -2 & 1\end{array}\right]$

adj. (A) = B' = $\left[\begin{array}{cc}-5 & -2 \\ -3 & 1\end{array}\right]$

Hence (2) is the correct answer.