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If $243^{3x}=27^{(4x-1)}$, then the value of $4^x$ is: |
4 -4 $\frac{1}{4}$ $\frac{1}{16}$ |
$\frac{1}{4}$ |
$243^{3x}=27^{(4x-1)}$ = $((3)^5)^{3x}=((3)^3)^{(4x-1)}$ 15x = 12x - 3 3x = - 3 x = - 1 Now, $4^{x}$ = 4-1 = \(\frac{1}{4}\) |
