If $243^{3x}=27^{(4x-1)}$, then the value of $4^x$ is:
Answer & explanation
Correct answer: option 3
$243^{3x}=27^{(4x-1)}$
= $((3)^5)^{3x}=((3)^3)^{(4x-1)}$
15x = 12x - 3
3x = - 3
x = - 1
Now, $4^{x}$ = 4-1
= \(\frac{1}{4}\)
If $243^{3x}=27^{(4x-1)}$, then the value of $4^x$ is:
Correct answer: option 3
$243^{3x}=27^{(4x-1)}$
= $((3)^5)^{3x}=((3)^3)^{(4x-1)}$
15x = 12x - 3
3x = - 3
x = - 1
Now, $4^{x}$ = 4-1
= \(\frac{1}{4}\)