The interval of increase of the function $f(x)=x-e^x+\tan(\frac{2π}{7})$ is
Answer & explanation
Correct answer: option 2
We have $f(x)=x-e^x+\tan(\frac{2π}{7})$
$⇒f'(x)=1-e^x$
For f(x) to be increasing, we must have
$f'(x) > 0 ⇒ 1 - e^x > 0 ⇒ e^x < 1$
$⇒x < 0.⇒x∈(−∞,0)$