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The value of $\underset{x→\frac{π}{4}}{\lim}\frac{\int\limits_{2}^{\sec^2x}f(t)dt}{x^2-\frac{π^2}{16}}$ is equal to |
$\frac{8}{π}f(2)$ $\frac{2}{π}f(2)$ $\frac{2}{π}f(\frac{1}{2})$ $4f(2)$ |
$\frac{8}{π}f(2)$ |
$\underset{x→\frac{π}{4}}{\lim}\frac{\int\limits_{2}^{\sec^2x}f(t)dt}{x^2-\frac{π^2}{16}}=\underset{x→\frac{π}{4}}{\lim}\frac{f(\sec^2x)×2\sec^2x\tan x}{2x}=\frac{8}{π}f(2)$ |
