The value of \( \begin{vmatrix}x & x+1\\x-1 & x\end{vmatrix} \) is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 1
Expanding the 2 × 2 determinant:
\( \displaystyle \begin{vmatrix}x & x+1\\x-1 & x\end{vmatrix}=x\cdot x-(x+1)(x-1) \)
\( =x^2-(x^2-1) \)
\( =1 \)
NCERT (2026-27 edition):
Determinant of a Matrix of Order Two
