Two bulbs marked 220 V, 200 W and 220 V, 1000 W, respectively, are connected in series to 220 V mains supply. The ratio of heat generated in them, respectively will be |
1:5 5:1 1:25 25:1 |
5:1 |
The correct answer is Option (2) → 5:1 Given: Bulb A: 220 V, 200 W Bulb B: 220 V, 1000 W First, calculate the resistance of each bulb using the formula: $R = \frac{V^2}{P}$ For Bulb A: $R_1 = \frac{220^2}{200} = \frac{48400}{200} = 242\,\Omega$ For Bulb B: $R_2 = \frac{220^2}{1000} = \frac{48400}{1000} = 48.4\,\Omega$ Since they are connected in series, the same current flows through both. Heat produced in time $t$ is given by: $H = I^2 R t$ So, the ratio of heat generated is proportional to their resistances: $\frac{H_1}{H_2} = \frac{R_1}{R_2} = \frac{242}{48.4} = 5:1$ |