If perimeter of a rhombus is 104 cm and length of one of its diagonals is 48 cm, then area of the rhombus (in cm²) is:

480

Perimeter of rhombus = 4×Side(a) = 4a = 104

a = 26

Length of one diagonal, D1 = 48

We know diagonals of a rhombus intersect each other at right angle

Thus, half of diagonal D1 = 24

Now consider right angle triangle right angled at intersection of diagonals with, P=24, H=26 and B=x (Here B is half of another diagonal)

H^2 = P^2 + B^2

26^2 = 24^2 + B^2

B^2 = 676 - 576

B = 10

Length of another diagonal, D2 = 2B = 20

Area of Rhombus = 0.5 (D1 D2) = 0.5 (48 × 20) = 480

The correct answer is Option (3) → 480