A 22 m long ladder (whose foot is on the ground) leans against a wall making an angle of $60^\circ$ with the wall. What is the height (in m) of the point where the ladder touches the wall from the ground?

11

⇒ cos \({60}^\circ\) = \(\frac{AB}{22}\)

⇒ \(\frac{1}{2}\) = \(\frac{AB}{22}\)

⇒ AB = \(\frac{22}{2}\) = 11m

Therefore, the height of the point where the ladder touches the wall from the ground is 11m.