If length of a rectangle is decreased by 8 cm, we get a square and the area of the square so formed is 224 square cm less than the area of the square formed, when breadth of the original rectangle is increased by 8 cm. Find the perimeter of the rectangle?

56 cm

The difference between l and b = 8

Let b = x

      l = x + 8

Square₁ = (x)²

Square₂ = (x + 8)²

Difference = 224

(x + 8)² - (x)² = 16x + 64 = 224

16x = 160 or x = 10

l = 18, b = 10

Perimeter = 2(l + b) = 2 x 28 = 56cm