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In Bohr's atomic model, the radius of the first orbit is $r_o$. The radius of the third orbit will be: |
$3r_o$ $9r_o$ $r_o$ $r_o/3$ |
$9r_o$ |
The correct answer is Option (2) → $9r_o$ Bohr's atomic model radius (r) is, $r_n∝n^2$ $⇒r_n=r_on^2$ [$r_o$ = Bohr's atomic radius] $⇒r_3(3)^2r_o=9r_o$ |
