A can do a certain work in 16 days. B is 50% more efficient then A. How many days will B and A together take to do the same job?
Answer & explanation
Correct answer: option 3
Ratio of efficiency of A and B = A : B
5 : 8
Ratio of time taken ∝ \(\frac{1}{efficiency}\)
Ratio of taken taken A : B
8 : 5 ⇒ (5 x 2 = 10)
↓
16(given)
Total work = L.C.M of 10 & 16 = 80
Time taken A and B together = \(\frac{Total\; work}{Efficiency}\)
= \(\frac{80}{13}\) = 6\(\frac{2}{13}\) days