A random variable X has the following probability distribution:
Determine: k |
$\frac{1}{10}$ $\frac{1}{9}$ $\frac{1}{8}$ $\frac{1}{7}$ |
$\frac{1}{10}$ |
The correct answer is Option (1) → $\frac{1}{10}$ We know that $Σp_i = 1$ $⇒ 0+ k + 2k + 2k + 3k + k^2 + 2k^2 + 7k^2 + k=1$ $⇒ 10k^2 + 9k-1=0⇒ (10k-1) (k + 1) = 0$ $⇒ k=\frac{1}{10},-1$ but $k$ cannot be negative $⇒ k=\frac{1}{10}$ |