Identify the correct equations for the emf of a cell at equilibrium.
Choose the correct answer from the options given below: |
(A) and (C) only (A) and (B) only (B) and (C) only (C) and (D) only |
(A) and (C) only |
The correct answer is option 1. (A) and (C) only. We know the Nernst equation is \(E_{cell} = E^0_{cell} - \frac{RT}{nF}ln Q\) \(E_{cell} = E^0_{cell} - \frac{RT}{nF}ln\frac{[Products]}{[Reactants]}\) [Since, \(Q = \frac{[Product]}{[Reactant]}\)] At equilibrium, \(E_{cell}= 0\) and \(Q = K_c\) \(E^0_{cell} = \frac{2.303RT}{nF}logK_c\) \(\Delta G^0 = -nFE^0_{cell}\) \(E^0_{cell} = E^0_{right} - E^0_{left}\) |