Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Applications of Derivatives

Question:

Global minimum value of f(x) = x8 + x6 – x4 – 2x3 – x2 – 2x + 9 is

Options:

0

1

5

9

Correct Answer:

5

Explanation:

We will get the minimum value of f(x) at x = 1 which is 5