Practicing Success
Practicing Success
CUET Preparation Today
The maximum value of $f(x)=\frac{\log x}{x}$ for x in $[2, \infty]$ is |
e 0 1 $\frac{1}{e}$ |
$\frac{1}{e}$ |
The correct answer is Option (4) - $\frac{1}{e}$ |
