CUET Preparation Today
A reaction is of second order with respect to a reactant. How will the rate of reaction be affected if the concentration of this reactant is doubled? |
It becomes \(\frac{1}{4}\) It becomes four times It becomes \(\frac{1}{2}\) It becomes two times |
It becomes four times |
Since Rate = K[A]2 Let [A] = a then Rate = Ka2 |
