A reaction is of second order with respect to a reactant. How will the rate of reaction be affected if the concentration of this reactant is doubled?
Answer & explanation
Correct answer: option 2
Since Rate = K[A]2
For second order reaction
Let [A] = a then Rate = Ka2
If [A] = 2a then Rate = K (2a)2 = 4 Ka2
∴Rate of reaction becomes 4 times.