A plane E-M waves of frequency 48 MHz travels in free space along the positive x-direction. At a particular point in space and time $\vec E = 10.2\hat j V/m$. The corresponding magnetic field $\vec B$ at that point will be:

$3.4×10^{-8}\hat k T$

The correct answer is Option (1) → $3.4×10^{-8}\hat k T$

The relationship between $\vec E$ and $\vec B$ is,

$B=\frac{E}{C}$

$=\frac{10.2}{3×10^8}$

$=3.4×10^{-8}\hat kT$