A plane E-M waves of frequency 48 MHz travels in free space along the positive x-direction. At a particular point in space and time $\vec E = 10.2\hat j V/m$. The corresponding magnetic field $\vec B$ at that point will be:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $3.4×10^{-8}\hat k T$
The relationship between $\vec E$ and $\vec B$ is,
$B=\frac{E}{C}$
$=\frac{10.2}{3×10^8}$
$=3.4×10^{-8}\hat kT$