Practicing Success
If sin A =\(\frac{9}{41}\) , then find the value of ( 120 secA + 27 cotA ) |
256 243 222 210 |
243 |
sin A =\(\frac{9}{41}\) =\(\frac{9}{41}\)=\(\frac{P}{H}\) [Triplet 9 , 40 , 41] B = 40 ⇒ 120 secA + 27 cotA = 120 × \(\frac{41}{40}\) + 27 × \(\frac{40}{9}\) = 123 + 120 = 243 |