If sin A = 9/41 , then find the value of ( 120 secA + 27 cotA )

sin A =\(\frac{9}{41}\)

=\(\frac{9}{41}\)=\(\frac{P}{H}\)   [Triplet 9 , 40 , 41]

B = 40

⇒ 120 secA + 27 cotA

= 120 × \(\frac{41}{40}\) + 27 × \(\frac{40}{9}\)

= 123 + 120 = 243