In the figure , a circle touches all the four sides of a quadrilateral ABCD whose sides AB = 6.5 cm, BC = 5.4 cm and CD = 5.3 cm. The length of AD is :
Answer & explanation
Correct answer: option 2
We have,
AB = 6.5 cm,
BC = 5.4 cm,
CD = 5.3 cm
We know that,
AP = AS, BP = BQ, CR = CQ, DR = DS
= (AP + PB) + (DR + RC) = (BQ + QC) + (AS + DS)
= AB + CD = AD + BC
= 6.5 + 5.3 = AD + 5.4
= 11.8 = AD + 5.4
= AD = 11.8 - 5.4 = 6.4 cm