If 2x = sin θ and $\frac{2}{x}=cosθ$ then the value of $4(x^2+\frac{1}{x^2})$ is :

2 0 4 1

1

Given :- 2x = sin θ &   \(\frac{2  }{x}\) = cosθ  Squaring both sides 4x² = sin²θ    -----(1) \(\frac{4  }{x²}\) = cos²θ      ----(2) Adding equation 1 and 2. sin²θ + cos²θ = 4x² + \(\frac{4  }{x²}\)  { sin²θ + cos²θ  = 1 } 1 = 4x² + \(\frac{4  }{x²}\) Ans :- 1