If λmax is 6563 Å, then wave length of second line for Balmer series will be

$\lambda=\frac{16}{3 R}$ $\lambda=\frac{36}{5 R}$ $\lambda=\frac{4}{3 R}$ None of the above

$\lambda=\frac{16}{3 R}$

For Balmer series $\frac{1}{\lambda}=R\left(\frac{1}{2^2}-\frac{1}{n^2}\right)$ where n = 3, 4, 5 For second line n = 4 So $\frac{1}{\lambda}=R\left(\frac{1}{2^2}-\frac{1}{4^2}\right)=\frac{3}{16} R \Rightarrow \lambda=\frac{16}{3 R}$