If $x=e^t$ and $y = e^{2t}$ then $\frac{d^2y}{dx^2}=$ |
$2x$ $2y$ 2 $\frac{1}{2x}$ |
2 |
The correct answer is Option (3) → 2 Given: $x = e^{t}$ and $y = e^{2t}$ $\frac{dy}{dt} = 2e^{2t}$ $\frac{dx}{dt} = e^{t}$ Then, $\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}} = \frac{2e^{2t}}{e^{t}} = 2e^{t}$ $\frac{d^2y}{dx^2} = \frac{d}{dx}\left(2e^{t}\right)$ = $\frac{d}{dt}(2e^{t}) \times \frac{dt}{dx}$ $= 2e^{t} \times \frac{1}{\frac{dx}{dt}} = 2e^{t} \times \frac{1}{e^{t}} = 2$ Therefore, $\displaystyle \frac{d^2y}{dx^2} = 2$. |