The equation of a plane passing through (1, 2, -3), (0, 0, 0) and perpendicular to the plane 3x – 5y + 2z = 11, is :
Answer & explanation
Correct answer: option 4
Let the required plane be
Ax + by + cz = 0
We have 3a – 5b + 2c = 0, a + 2b – 3c = 0
$\Rightarrow \frac{a}{15-4}=\frac{b}{2+9}=\frac{c}{6+5}$
$\Rightarrow a: b: c=11: 11: 11$
Thus plan is x + y + z = 0