The length of a rectangle is increased by $16\frac{2}{3}$%. By what approximate percentage should its breadth be decreased so that the area of the rectangle remains unchanged?

14.29%

$16\frac{2}{3}$% = \(\frac{1}{6}\) = \(\frac{Increment}{Old \; measurement}\) 

               Old               New

Length=   6                 7

Breadth = 7                6 = 1 ( difference )

So , percentage should its breadth be decreased = \(\frac{(7-6) × 100}{7}\) = 14.29%