The length of a rectangle is increased by $16\frac{2}{3}$%. By what approximate percentage should its breadth be decreased so that the area of the rectangle remains unchanged?
Answer & explanation
Correct answer: option 2
$16\frac{2}{3}$% = \(\frac{1}{6}\) = \(\frac{Increment}{Old \; measurement}\)
Old New
Length= 6 7
Breadth = 7 6 = 1 ( difference )
So , percentage should its breadth be decreased = \(\frac{(7-6) × 100}{7}\) = 14.29%