Pramod walks 10 m towards east then he turns right and goes 8 m, he again turns right and walks 4 m. Now the distance of Pramod from initial point is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 10 m
Each turn is taken from the direction Pramod is facing at that moment:
Walking East, a right turn is South: 8 m South
Walking South, a right turn is West: 4 m West
He ends \(10-4=6\) m East and 8 m South of the start. These two legs are at right angles, so by Pythagoras’ theorem the distance is \(\sqrt{6^2+8^2}=\sqrt{100}=10\) m.