Practicing Success
The set of values of parameter 'a' for which the function $f: R→ R$ defined by $f (x) = ax + \sin x$ is bijective, is |
$[-1,1]$ $R-(-1,1)$ $R-[-1,1]$ $(-1,1)$ |
$R-[-1,1]$ |
If f(x) is an injection, then $f'(x) >0$ or, $f'(x) <0$ for all $x ∈ R$ $⇒a + \cos x >0$ or, $a + \cos x < 0$ for all $x ∈ R$ $⇒a > 1$ or, $a <-1$ $⇒a ∈ R-[-1,1]$. We observe that $f(x)→ ∞$ as $x → ∞$ and $f (x) → -∞$ as $x→ -∞$. Therefore, range of $f = R$. So, f is surjective for all values of a. Hence, f is a bijection if $a ∈R -[-1,1]$. |