The circumference of a circle exceeds its diameter by 60 cm. The area of the circle is: Take($\pi=\frac{22}{7}$)

346.5 $cm^2$ 616 $cm^2$ 536 $cm^2$ 1078 $cm^2$

616 $cm^2$

We know that the circumference of the circle = 2πr and the area of the circle = πr2 Now, according to the question, 2πr – 2r = 60 = 2r(\(\frac{22}{7}\) – 1) = 60 = r × \(\frac{15}{7}\) = 30 = r = 14 cm Area of the circle =  \(\frac{22}{7}\) × 14 × 14 = 616 cm2