Practicing Success
Practicing Success
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If $x^{2 a}=y^{2 b}=z^{2 c} \neq 0$ and $x^2=y z$, then the value of $\frac{a b+b c+c a}{b c}$ is: |
3ac 3bc 3ab 3 |
3 |
$x^{2 a}=y^{2 b}=z^{2 c} \neq 0$ $x^2=y z$ Then the value of $\frac{a b+b c+c a}{b c}$ Put x = y = z = a = b = c $\frac{a b+b c+c a}{b c}$ = $\frac{1 × 1 + 1 × 1 + 1 × 1}{1 × 1}$ = 3 |
