Which one of the following elements forms halide in +2 oxidation state only?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → Nickel
The highest oxidation state a 3d metal shows in its halides depends on how easily it loses electrons and on the halogen. Fluorine, the most electronegative halogen, brings out the highest states. Along the series the higher oxidation states become less stable, and after the middle of the series the +2 state dominates.
Manganese, iron and cobalt also form halides in higher oxidation states (such as \( \ce{MnF3} \), \( \ce{FeCl3} \) and \( \ce{CoF3} \)), but nickel forms only the +2 halides \( \ce{NiX2} \). So the element that forms halides only in the +2 oxidation state is nickel.
NCERT (2026-27 edition):
Trends in Stability of Higher Oxidation States – “… Table 4.5 shows the stable halides of the 3d series of transition metals. The highest oxidation numbers are achieved in TiX4 (tetrahalides), VF5 and CrF6. The +7 state for Mn is not represented in simple halides but MnO3F is known, and beyond Mn no metal has a trihalide except FeX3 and CoF3.”
| Oxidation number | Ti | V | Cr | Mn | Fe | Co | Ni | Cu | Zn |
|---|---|---|---|---|---|---|---|---|---|
| +6 | CrF6 | ||||||||
| +5 | VF5 | CrF5 | |||||||
| +4 | TiX4 | VX4I | CrX4 | MnF4 | |||||
| +3 | TiX3 | VX3 | CrX3 | MnF3 | FeX3I | CoF3 | |||
| +2 | TiX2III | VX2 | CrX2 | MnX2 | FeX2 | CoX2 | NiX2 | CuX2II | ZnX2 |
| +1 | CuXIII |
Key: X = F → I; XI = F → Br; XII = F, Cl; XIII = Cl → I