Practicing Success
Practicing Success
CUET Preparation Today
Let g(x) be the inverse of the function f (x) and $f'(x)=\frac{1}{1+x^3}$. Then g'(x) is equal to |
$\frac{1}{1+(g(x))^3}$ $\frac{1}{1+(f(x))^3}$ $1+(g(x))^3$ $1+(f(x))^3$ |
$1+(g(x))^3$ |
$g(x)= f^{−1} ⇒x=f(g(x))$ $1=f'(g(x)).g'(x)$ $g'(x)=\frac{1}{f'(g(x))}=1+(g(x))^3$ |
