Let g(x) be the inverse of the function f (x) and $f'(x)=\frac{1}{1+x^3}$. Then g'(x) is equal to
Answer & explanation
Correct answer: option 3
$g(x)= f^{−1} ⇒x=f(g(x))$
$1=f'(g(x)).g'(x)$
$g'(x)=\frac{1}{f'(g(x))}=1+(g(x))^3$
Let g(x) be the inverse of the function f (x) and $f'(x)=\frac{1}{1+x^3}$. Then g'(x) is equal to
Correct answer: option 3
$g(x)= f^{−1} ⇒x=f(g(x))$
$1=f'(g(x)).g'(x)$
$g'(x)=\frac{1}{f'(g(x))}=1+(g(x))^3$