A coin is tossed twice. Then

Match List-I with List-II:

Choose the correct answer from the options given below:

(A)-(I), (B)-(III), (C)-(II), (D)-(IV)

The correct answer is Option (2) → (A)-(I), (B)-(III), (C)-(II), (D)-(IV)

$\text{Sample space }=\{HH,HT,TH,TT\}.$

$(A)\;P(\text{exactly 2 heads})=\frac{1}{4}\Rightarrow(I).$

$(B)\;P(\text{at least 1 head})=\frac{3}{4}\Rightarrow(III).$

$(C)\;P(\text{at most 2 heads})=1\Rightarrow(II).$

$(D)\;P(\text{exactly 1 head})=\frac{2}{4}=\frac{1}{2}\Rightarrow(IV).$

$(A)\rightarrow(I),\;(B)\rightarrow(III),\;(C)\rightarrow(II),\;(D)\rightarrow(IV).$