Three solid glass balls of radii ‘r’ cm, 6 cm and 8 cm are melted into a solid sphere of radius 9 cm. Find the value of ‘r’. |
$\frac{1}{4}$cm $\frac{1}{3}$cm $\frac{1}{2}$cm 1 cm |
1 cm |
Given that the radii of three solid glass balls is ‘r’ cm, 6 cm and 8 cm, sum of the volumes of the three balls $=\frac{4}{3}πr^3+\frac{4}{3}π(6)^3+\frac{4}{3}π(8)^3$ $=\frac{4}{3}π(r^3+6^3+8^3)cm^3$ The volume of the solid sphere of radius 9 cm $=\frac{4}{3}π(9)^3=243×4π$ $∴243×4π=\frac{4}{3}π(r^3+728)$ ⇒ r = 1 |