CUET Preparation Today
Charge Q is placed at a distance r from a uniformly charged rod having 'λ' as linear charge density. The electrostatic force between them (Length of rod = L) is:
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$\frac{kQλ}{(r+\frac{L}{2})}$ $\frac{kQλL}{r(r+L)}$ $\frac{kQλ}{(r+\frac{L}{2})^2}$ $\frac{kQλ}{(r^2+L^2)}$ |
$\frac{kQλL}{r(r+L)}$ |
The correct answer is Option (2) → $\frac{kQλL}{r(r+L)}$ |
