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Two numbers are in the ratio of 9 : 7. If the larger number is 56 more than one-seventh of the smaller, then what is the sum of two numbers? |
72 130 112 96 |
112 |
A : B 9 : 7 According to the question, ⇒ 9x = \(\frac{1}{7}\) × 7x + 56 ⇒ 9x = x + 56 ⇒ 8x = 56 ⇒ x = 7, ⇒ Sum of A and B = (9 + 7)x = 16x = 16 × 7 = 112. |
