Two numbers are in the ratio of 9 : 7. If the larger number is 56 more than one-seventh of the smaller, then what is the sum of two numbers?
Answer & explanation
Correct answer: option 3
A : B
9 : 7
According to the question,
⇒ 9x = \(\frac{1}{7}\) × 7x + 56
⇒ 9x = x + 56
⇒ 8x = 56
⇒ x = 7,
⇒ Sum of A and B = (9 + 7)x = 16x = 16 × 7 = 112.