CUET Preparation Today
CUET
Physics
Gravitation
If the time of revolution of a satellite is T, then Kinetic energy is proportional to
1/T
1/T2
1/T3
T -2/3
Orbital velocity v = $\frac{2 \pi r}{T}$
Hence, KE ∝ $\frac{1}{T^2}$
