Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

If the time of revolution of a satellite is T, then Kinetic energy is proportional to

Options:

1/T

1/T2

1/T3

-2/3

Correct Answer:

1/T2

Explanation:

Orbital velocity v = $\frac{2 \pi r}{T}$

Hence, KE ∝ $\frac{1}{T^2}$