If the time of revolution of a satellite is T, then Kinetic energy is proportional to
Answer & explanation
Correct answer: option 2
Orbital velocity v = $\frac{2 \pi r}{T}$
Hence, KE ∝ $\frac{1}{T^2}$
If the time of revolution of a satellite is T, then Kinetic energy is proportional to
Correct answer: option 2
Orbital velocity v = $\frac{2 \pi r}{T}$
Hence, KE ∝ $\frac{1}{T^2}$