Match List-I (biomolecule) with List-II (characteristics)
|
List-I Biomolecule |
List-II Characteristics |
|
(A) Lactose |
(I) Menstrual cycle |
|
(B) Glycine |
(II) Bleeding gums |
|
(C) Ascorbic acid |
(III) Optically inactive |
|
(D) Estradiol |
(IV) Reducing sugar |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
Each biomolecule is matched by the one property it is best known for: a free carbonyl group for a sugar, a chiral carbon for an amino acid, the deficiency disease for a vitamin and the body function for a hormone.
(A) Lactose — This matches (IV) Reducing sugar. Lactose (milk sugar) is made of β-D-galactose and β-D-glucose, joined from C-1 of galactose to C-4 of glucose. C-1 of the glucose unit stays free as a hemiacetal, which opens to a –CHO group, so lactose reduces Tollens’ reagent and Fehling’s solution.
(B) Glycine — This matches (III) Optically inactive. Glycine, \( \ce{H2N-CH2-COOH} \), has two hydrogen atoms on its α-carbon, so it has no chiral carbon; it is the only one of the common α-amino acids that is not optically active.
(C) Ascorbic acid — This matches (II) Bleeding gums. Ascorbic acid is vitamin C; its deficiency causes scurvy, whose sign is bleeding gums.
(D) Estradiol — This matches (I) Menstrual cycle. Estradiol is a steroid female sex hormone; it controls the development of secondary female characters and takes part in the control of the menstrual cycle.
Shortcut: (A)-(IV) appears in Options (1) and (4); (C)-(II) then leaves only Option (4).