An a.c voltage is applied to a resistor of resistance \( 5\,\Omega \) and an inductor having inductive reactance of \( 5\,\Omega \) connected in series. The phase difference between applied voltage and the current in the circuit is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \( \displaystyle\frac{\pi}{4} \)
In a series LR circuit the voltage leads the current by the phase angle \( \phi \), given by the ratio of the inductive reactance to the resistance.
\( \displaystyle \tan\phi = \frac{X_L}{R} \)
\( X_L = 5\,\Omega \)
\( R = 5\,\Omega \)
\( \displaystyle \tan\phi = \frac{5\,\Omega}{5\,\Omega} = 1 \)
\( \displaystyle \phi = 45^\circ = \frac{\pi}{4} \)