An ac voltage is applied to a resistor of resistance 5Ω and an inductor having inductive reactance of 5Ω connected in series. The phase difference between applied voltage and the current in the circuit is:

$\frac{π}{4}$

The correct answer is Option (2) → $\frac{π}{4}$

The phase difference between the voltage and the current in an AC circuit is,

$\tan\phi=\frac{X_L}{R}=\frac{5}{5}$

$\tan\phi=1$

$⇒\phi=\tan^{-1}(1)=45°$