Three vessels whose capacities are 3 : 1 : 4 are completely filled with milk and water. The ratio of milk and water in these vessels are 4 : 1, 3 : 2 and 1 : 3 respectively. Taking \(\frac{1}{3}\) of first, \(\frac{1}{4}\) of second and \(\frac{1}{5}\) of the third mixture, a new mixture kept in a new vessel is prepared. The percentage of water in the new mixture is (approx):

44

          Milk    :    Water   :    Total

1st :     4      :        1      :      5      ) × 4 × 3 × \(\frac{1}{3}\)

2nd:     3      :        2      :      5      ) × 4 × 1 × \(\frac{1}{4}\)

3rd:      1      :       3      :      4      ) × 5 × 4 × \(\frac{1}{5}\)

⇒       Milk     :    Water

1st :    16      :       4

2nd:     3      :        2

3rd:     4       :       12   

Total :  23     :       18    =   41 (Total)

Water Percentage = \(\frac{18}{41}\) × 100 = 43.9% = 44% (approx)