Three vessels whose capacities are 3 : 1 : 4 are completely filled with milk and water. The ratio of milk and water in these vessels are 4 : 1, 3 : 2 and 1 : 3 respectively. Taking \(\frac{1}{3}\) of first, \(\frac{1}{4}\) of second and \(\frac{1}{5}\) of the third mixture, a new mixture kept in a new vessel is prepared. The percentage of water in the new mixture is (approx):
Answer & explanation
Correct answer: option 3
Milk : Water : Total
1st : 4 : 1 : 5 ) × 4 × 3 × \(\frac{1}{3}\)
2nd: 3 : 2 : 5 ) × 4 × 1 × \(\frac{1}{4}\)
3rd: 1 : 3 : 4 ) × 5 × 4 × \(\frac{1}{5}\)
⇒ Milk : Water
1st : 16 : 4
2nd: 3 : 2
3rd: 4 : 12
Total : 23 : 18 = 41 (Total)
Water Percentage = \(\frac{18}{41}\) × 100 = 43.9% = 44% (approx)