24 women and 9 men can complete a certain piece of work in 18 days. Each women takes twice the amount of time taken by a man to finish the work. In how many days can only 9 men finish the same work?
Answer & explanation
Correct answer: option 1
24W + 9M = 18 days,
Man : Women
Time 1 : 2
Efficiency 2 : 1 (Efficiency α \(\frac{1}{Time}\))
⇒ Total work = [24(1) + 9(2)] x 18 = 42 x 18 = 756 units, ..(Efficiency × Days = Total work)
⇒ Time required by 9 Man to complete the total work = \(\frac{756}{9(2)}\) = \(\frac{756}{18}\) = 42 days. ..(\(\frac{Work}{Efficiency}\) = Time)