Answer & explanation
Correct answer: option 2
$ \eta = \frac{P_{out}}{P_{in}} = \frac{V_SI_S}{V_PI_P} = \frac{230\times I_S}{2300\times 5} = 0.9$
$ I_S = 45A$
Correct answer: option 2
$ \eta = \frac{P_{out}}{P_{in}} = \frac{V_SI_S}{V_PI_P} = \frac{230\times I_S}{2300\times 5} = 0.9$
$ I_S = 45A$