Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Differential Equations

Question:

The general solution of the differential equation $ydx+xdy =0$ is :

Options:

$xy = C, $ where C is a constant.

$\frac{1}{x}+\frac{1}{y}=C,$ where C is a constant.

$logx.logy\, y=C,$ where C is a constant.

$x+y=C,$ where C is a constant

Correct Answer:

$xy = C, $ where C is a constant.

Explanation:

The correct answer is Option (1) → $xy = C, $ where C is a constant.

$\int ydx+xdy =0$

so $\int d(xy)=\int 0$

$⇒xy=c$